Found “e” in the primes (maybe)

Arrange the primes so that the distance between consecutives must keep growing:

2 3 5

7 11

13 17

19 23 29

31 37

41 43 47 53

59 61 67

71 73 79

83 89 97

101 103 107

109 113 127

131 137

139 149

151 157

163 167 173

179 181 189

193 197

199 211

223 227 229

233 239

241 251

257 263

269 271 277

281 283 293 307

311 313 317 331

337 347

349 353 359 367

373 379

383 389

397 401 409 419

421 431

433 439

443 449 457

461 463 467 479

487 491 499

503 509 521

523 541

547 557

563 569

571 577 587

593 599

601 607

613 617

619 631

641 643 647 653

659 661 673

677 683 691

701 709 719

727 733

739 743 751

757 761 769

773 787

797 809

811 821

823 827

829 839 853

857 859 863 877

881 883 887 907

911 919 929

953 967

971 977

Total average value of each row: 163 / 60 = 2.71666… ≈ e

983 991

997 1009

1013 1019

1021 1031

1033 1039 1049

1051 1061

1063 1069 1087

1091 1093 1097 1103

1109 1117

1123 1129 1151

1153 1163

1171 1181

1187 1193 1201 1213

1217 1223

1229 1231 1237 1249

1259 1277

1279 1283 1289

1291 1297

1301 1303 1307 1319

1321 1327 1361

1367 1373 1381 1399

1409 1423

Total average value of each row: 222 / 82 ≈ 2.707 ≈ e

I stumbled upon this tonight, no idea if it really converges to “e” or if this has already been found.

submitted by /u/RockofStrength
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Nevin Manimala

Nevin Manimala is interested in blogging and finding new blogs https://nevinmanimala.com

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